(3x+9)(3x-9)=0

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Solution for (3x+9)(3x-9)=0 equation:



(3x+9)(3x-9)=0
We use the square of the difference formula
9x^2-81=0
a = 9; b = 0; c = -81;
Δ = b2-4ac
Δ = 02-4·9·(-81)
Δ = 2916
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2916}=54$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-54}{2*9}=\frac{-54}{18} =-3 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+54}{2*9}=\frac{54}{18} =3 $

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