(3x+8)+(x-6)=40

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Solution for (3x+8)+(x-6)=40 equation: 



(3x+8)+(x-6)=40

We move all terms to the left:

(3x+8)+(x-6)-(40)=0

We get rid of parentheses

3x+x+8-6-40=0

We add all the numbers together, and all the variables

4x-38=0

We move all terms containing x to the left, all other terms to the right

4x=38

x=38/4

x=9+1/2

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