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(3x+8)(x+4)=180
We move all terms to the left:
(3x+8)(x+4)-(180)=0
We multiply parentheses ..
(+3x^2+12x+8x+32)-180=0
We get rid of parentheses
3x^2+12x+8x+32-180=0
We add all the numbers together, and all the variables
3x^2+20x-148=0
a = 3; b = 20; c = -148;
Δ = b2-4ac
Δ = 202-4·3·(-148)
Δ = 2176
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2176}=\sqrt{64*34}=\sqrt{64}*\sqrt{34}=8\sqrt{34}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-8\sqrt{34}}{2*3}=\frac{-20-8\sqrt{34}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+8\sqrt{34}}{2*3}=\frac{-20+8\sqrt{34}}{6} $
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