(3x+7)+63=(5x+50)

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Solution for (3x+7)+63=(5x+50) equation: 



(3x+7)+63=(5x+50)

We move all terms to the left:

(3x+7)+63-((5x+50))=0

We get rid of parentheses

3x-((5x+50))+7+63=0



We calculate terms in parentheses: -((5x+50)), so:

(5x+50)

We get rid of parentheses

5x+50

Back to the equation:

-(5x+50)



We add all the numbers together, and all the variables

3x-(5x+50)+70=0

We get rid of parentheses

3x-5x-50+70=0

We add all the numbers together, and all the variables

-2x+20=0

We move all terms containing x to the left, all other terms to the right

-2x=-20

x=-20/-2

x=+10

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