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(3x+7)(5x+3)=0
We multiply parentheses ..
(+15x^2+9x+35x+21)=0
We get rid of parentheses
15x^2+9x+35x+21=0
We add all the numbers together, and all the variables
15x^2+44x+21=0
a = 15; b = 44; c = +21;
Δ = b2-4ac
Δ = 442-4·15·21
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{676}=26$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(44)-26}{2*15}=\frac{-70}{30} =-2+1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(44)+26}{2*15}=\frac{-18}{30} =-3/5 $
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