(3x+68)=(2x-13)

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Solution for (3x+68)=(2x-13) equation: 



(3x+68)=(2x-13)

We move all terms to the left:

(3x+68)-((2x-13))=0

We get rid of parentheses

3x-((2x-13))+68=0



We calculate terms in parentheses: -((2x-13)), so:

(2x-13)

We get rid of parentheses

2x-13

Back to the equation:

-(2x-13)



We get rid of parentheses

3x-2x+13+68=0

We add all the numbers together, and all the variables

x+81=0

We move all terms containing x to the left, all other terms to the right

x=-81

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