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(3x+6)=(6x^2+9x+11)
We move all terms to the left:
(3x+6)-((6x^2+9x+11))=0
We get rid of parentheses
3x-((6x^2+9x+11))+6=0
We calculate terms in parentheses: -((6x^2+9x+11)), so:We get rid of parentheses
(6x^2+9x+11)
We get rid of parentheses
6x^2+9x+11
Back to the equation:
-(6x^2+9x+11)
-6x^2+3x-9x-11+6=0
We add all the numbers together, and all the variables
-6x^2-6x-5=0
a = -6; b = -6; c = -5;
Δ = b2-4ac
Δ = -62-4·(-6)·(-5)
Δ = -84
Delta is less than zero, so there is no solution for the equation
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