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(3x+6)-2x=-(-12)+3x
We move all terms to the left:
(3x+6)-2x-(-(-12)+3x)=0
We add all the numbers together, and all the variables
-2x+(3x+6)-(-(-12)+3x)=0
We get rid of parentheses
-2x+3x-(-(-12)+3x)+6=0
We calculate terms in parentheses: -(-(-12)+3x), so:We add all the numbers together, and all the variables
-(-12)+3x
determiningTheFunctionDomain 3x-(-12)
We add all the numbers together, and all the variables
3x+12
Back to the equation:
-(3x+12)
x-(3x+12)+6=0
We get rid of parentheses
x-3x-12+6=0
We add all the numbers together, and all the variables
-2x-6=0
We move all terms containing x to the left, all other terms to the right
-2x=6
x=6/-2
x=-3
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