(3x+6)+(2x+18)=156

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Solution for (3x+6)+(2x+18)=156 equation: 



(3x+6)+(2x+18)=156

We move all terms to the left:

(3x+6)+(2x+18)-(156)=0

We get rid of parentheses

3x+2x+6+18-156=0

We add all the numbers together, and all the variables

5x-132=0

We move all terms containing x to the left, all other terms to the right

5x=132

x=132/5

x=26+2/5

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