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(3x+6)(x+8)=x
We move all terms to the left:
(3x+6)(x+8)-(x)=0
We add all the numbers together, and all the variables
-1x+(3x+6)(x+8)=0
We multiply parentheses ..
(+3x^2+24x+6x+48)-1x=0
We get rid of parentheses
3x^2+24x+6x-1x+48=0
We add all the numbers together, and all the variables
3x^2+29x+48=0
a = 3; b = 29; c = +48;
Δ = b2-4ac
Δ = 292-4·3·48
Δ = 265
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(29)-\sqrt{265}}{2*3}=\frac{-29-\sqrt{265}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(29)+\sqrt{265}}{2*3}=\frac{-29+\sqrt{265}}{6} $
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