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(3x+6)(2x-10)=0.
We multiply parentheses ..
(+6x^2-30x+12x-60)=0
We get rid of parentheses
6x^2-30x+12x-60=0
We add all the numbers together, and all the variables
6x^2-18x-60=0
a = 6; b = -18; c = -60;
Δ = b2-4ac
Δ = -182-4·6·(-60)
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1764}=42$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-42}{2*6}=\frac{-24}{12} =-2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+42}{2*6}=\frac{60}{12} =5 $
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