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(3x+5=x+3)
We move all terms to the left:
(3x+5-(x+3))=0
We calculate terms in parentheses: +(3x+5-(x+3)), so:We get rid of parentheses
3x+5-(x+3)
determiningTheFunctionDomain 3x-(x+3)+5
We get rid of parentheses
3x-x-3+5
We add all the numbers together, and all the variables
2x+2
Back to the equation:
+(2x+2)
2x+2=0
We move all terms containing x to the left, all other terms to the right
2x=-2
x=-2/2
x=-1
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