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(3x+5)=(x+19)
We move all terms to the left:
(3x+5)-((x+19))=0
We get rid of parentheses
3x-((x+19))+5=0
We calculate terms in parentheses: -((x+19)), so:We get rid of parentheses
(x+19)
We get rid of parentheses
x+19
Back to the equation:
-(x+19)
3x-x-19+5=0
We add all the numbers together, and all the variables
2x-14=0
We move all terms containing x to the left, all other terms to the right
2x=14
x=14/2
x=7
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