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(3x+5)=(x+17)
We move all terms to the left:
(3x+5)-((x+17))=0
We get rid of parentheses
3x-((x+17))+5=0
We calculate terms in parentheses: -((x+17)), so:We get rid of parentheses
(x+17)
We get rid of parentheses
x+17
Back to the equation:
-(x+17)
3x-x-17+5=0
We add all the numbers together, and all the variables
2x-12=0
We move all terms containing x to the left, all other terms to the right
2x=12
x=12/2
x=6
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