(3x+5)=(7x-2)

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Solution for (3x+5)=(7x-2) equation: 



(3x+5)=(7x-2)

We move all terms to the left:

(3x+5)-((7x-2))=0

We get rid of parentheses

3x-((7x-2))+5=0



We calculate terms in parentheses: -((7x-2)), so:

(7x-2)

We get rid of parentheses

7x-2

Back to the equation:

-(7x-2)



We get rid of parentheses

3x-7x+2+5=0

We add all the numbers together, and all the variables

-4x+7=0

We move all terms containing x to the left, all other terms to the right

-4x=-7

x=-7/-4

x=1+3/4

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