(3x+5)=(2x+68)

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Solution for (3x+5)=(2x+68) equation: 



(3x+5)=(2x+68)

We move all terms to the left:

(3x+5)-((2x+68))=0

We get rid of parentheses

3x-((2x+68))+5=0



We calculate terms in parentheses: -((2x+68)), so:

(2x+68)

We get rid of parentheses

2x+68

Back to the equation:

-(2x+68)



We get rid of parentheses

3x-2x-68+5=0

We add all the numbers together, and all the variables

x-63=0

We move all terms containing x to the left, all other terms to the right

x=63

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