(3x+5)/7x^2-(2x+3)/7x^2=0

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Solution for (3x+5)/7x^2-(2x+3)/7x^2=0 equation: 


x in (-oo:+oo)

x^2*((3*x+5)/7)-(x^2*((2*x+3)/7)) = 0

(x^2*(3*x+5))/7+(-1*x^2*(2*x+3))/7 = 0

x^2*(3*x+5)-1*x^2*(2*x+3) = 0

x^3+2*x^2 = 0

x^3+2*x^2 = 0

x^2*(x+2) = 0

x+2 = 0 // - 2

x = -2

x^2*(x+2) = 0

(x^2*(x+2))/7 = 0

(x^2*(x+2))/7 = 0 // * 7

x^2*(x+2) = 0

( x+2 )

x+2 = 0 // - 2

x = -2

( x^2 )

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in { -2, 0 }

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