(3x+5)/(2x-3)=10

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Solution for (3x+5)/(2x-3)=10 equation: 



(3x+5)/(2x-3)=10

We move all terms to the left:

(3x+5)/(2x-3)-(10)=0



Domain of the equation: (2x-3)!=0

We move all terms containing x to the left, all other terms to the right

2x!=3

x!=3/2

x!=1+1/2

x∈R



We multiply all the terms by the denominator


(3x+5)-10*(2x-3)=0

We multiply parentheses

(3x+5)-20x+30=0

We get rid of parentheses

3x-20x+5+30=0

We add all the numbers together, and all the variables

-17x+35=0

We move all terms containing x to the left, all other terms to the right

-17x=-35

x=-35/-17

x=2+1/17

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