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(3x+5)(5x+15)=1880
We move all terms to the left:
(3x+5)(5x+15)-(1880)=0
We multiply parentheses ..
(+15x^2+45x+25x+75)-1880=0
We get rid of parentheses
15x^2+45x+25x+75-1880=0
We add all the numbers together, and all the variables
15x^2+70x-1805=0
a = 15; b = 70; c = -1805;
Δ = b2-4ac
Δ = 702-4·15·(-1805)
Δ = 113200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{113200}=\sqrt{400*283}=\sqrt{400}*\sqrt{283}=20\sqrt{283}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(70)-20\sqrt{283}}{2*15}=\frac{-70-20\sqrt{283}}{30} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(70)+20\sqrt{283}}{2*15}=\frac{-70+20\sqrt{283}}{30} $
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