If it's not what You are looking for type in the equation solver your own equation and let us solve it.
(3x+5)(4x+11)=0
We multiply parentheses ..
(+12x^2+33x+20x+55)=0
We get rid of parentheses
12x^2+33x+20x+55=0
We add all the numbers together, and all the variables
12x^2+53x+55=0
a = 12; b = 53; c = +55;
Δ = b2-4ac
Δ = 532-4·12·55
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{169}=13$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(53)-13}{2*12}=\frac{-66}{24} =-2+3/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(53)+13}{2*12}=\frac{-40}{24} =-1+2/3 $
| 5x+29+8x-17=180 | | 5e+1=6e-3e-(-5) | | 2a+94=14a+70 | | 5s=s+12 | | -2-m=7-m-9 | | 18h+15=3(8h-19) | | 1.6n+8.9=3.3 | | -3(2u+5)=-15-16u | | -14t+3-10t=15-20t | | -4(3j+1)=-3j | | 19-11d=-2-11d-10 | | -6(m-3)=-3m | | -15+12g+20=12g+5 | | 4(-4y-5)=-20-16y | | 17r+12=12+2r+15r | | 15+r=-3r+3r-1 | | -5p+10+5=15-5p | | 5-10+16s=16s-5 | | -(-2x+1)+(x-7)=13 | | 12y+9=-11+18y-4y | | 2-7s=10-9s | | x+3x+9=0 | | -19-18+j=-7j+19 | | -17q+5=7-2-17q | | 15+4k=43 | | 7v-8=7v+7 | | 4x+1+2x+3=2x | | 11+3w=14+3w-3 | | 5.8^x+2=5^7x | | -2n+9=6-2n+3 | | (15x-3)=(7x+15) | | 8-5^3x=6 |