(3x+4y)+5z=3x+(4y+5z)

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Solution for (3x+4y)+5z=3x+(4y+5z) equation:


Simplifying
(3x + 4y) + 5z = 3x + (4y + 5z)

Remove parenthesis around (3x + 4y)
3x + 4y + 5z = 3x + (4y + 5z)

Remove parenthesis around (4y + 5z)
3x + 4y + 5z = 3x + 4y + 5z

Add '-3x' to each side of the equation.
3x + 4y + -3x + 5z = 3x + 4y + -3x + 5z

Reorder the terms:
3x + -3x + 4y + 5z = 3x + 4y + -3x + 5z

Combine like terms: 3x + -3x = 0
0 + 4y + 5z = 3x + 4y + -3x + 5z
4y + 5z = 3x + 4y + -3x + 5z

Reorder the terms:
4y + 5z = 3x + -3x + 4y + 5z

Combine like terms: 3x + -3x = 0
4y + 5z = 0 + 4y + 5z
4y + 5z = 4y + 5z

Add '-4y' to each side of the equation.
4y + -4y + 5z = 4y + -4y + 5z

Combine like terms: 4y + -4y = 0
0 + 5z = 4y + -4y + 5z
5z = 4y + -4y + 5z

Combine like terms: 4y + -4y = 0
5z = 0 + 5z
5z = 5z

Add '-5z' to each side of the equation.
5z + -5z = 5z + -5z

Combine like terms: 5z + -5z = 0
0 = 5z + -5z

Combine like terms: 5z + -5z = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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