(3x+4x+7x)+(19-11+4)=180

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Solution for (3x+4x+7x)+(19-11+4)=180 equation: 



(3x+4x+7x)+(19-11+4)=180

We move all terms to the left:

(3x+4x+7x)+(19-11+4)-(180)=0

determiningTheFunctionDomain
(3x+4x+7x)-180+(19-11+4)=0

We add all the numbers together, and all the variables

(+14x)-180+12=0

We add all the numbers together, and all the variables

(+14x)-168=0

We get rid of parentheses

14x-168=0

We move all terms containing x to the left, all other terms to the right

14x=168

x=168/14

x=12

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