(3x+4i)(4x+3i)=2

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Solution for (3x+4i)(4x+3i)=2 equation:


Simplifying
(3x + 4i)(4x + 3i) = 2

Reorder the terms:
(4i + 3x)(4x + 3i) = 2

Reorder the terms:
(4i + 3x)(3i + 4x) = 2

Multiply (4i + 3x) * (3i + 4x)
(4i * (3i + 4x) + 3x * (3i + 4x)) = 2
((3i * 4i + 4x * 4i) + 3x * (3i + 4x)) = 2

Reorder the terms:
((16ix + 12i2) + 3x * (3i + 4x)) = 2
((16ix + 12i2) + 3x * (3i + 4x)) = 2
(16ix + 12i2 + (3i * 3x + 4x * 3x)) = 2
(16ix + 12i2 + (9ix + 12x2)) = 2

Reorder the terms:
(16ix + 9ix + 12i2 + 12x2) = 2

Combine like terms: 16ix + 9ix = 25ix
(25ix + 12i2 + 12x2) = 2

Solving
25ix + 12i2 + 12x2 = 2

Solving for variable 'i'.

Reorder the terms:
-2 + 25ix + 12i2 + 12x2 = 2 + -2

Combine like terms: 2 + -2 = 0
-2 + 25ix + 12i2 + 12x2 = 0

The solution to this equation could not be determined.

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