(3x+41)=(7x+9)

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Solution for (3x+41)=(7x+9) equation: 



(3x+41)=(7x+9)

We move all terms to the left:

(3x+41)-((7x+9))=0

We get rid of parentheses

3x-((7x+9))+41=0



We calculate terms in parentheses: -((7x+9)), so:

(7x+9)

We get rid of parentheses

7x+9

Back to the equation:

-(7x+9)



We get rid of parentheses

3x-7x-9+41=0

We add all the numbers together, and all the variables

-4x+32=0

We move all terms containing x to the left, all other terms to the right

-4x=-32

x=-32/-4

x=+8

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