(3x+41)=(4x+35)

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Solution for (3x+41)=(4x+35) equation: 



(3x+41)=(4x+35)

We move all terms to the left:

(3x+41)-((4x+35))=0

We get rid of parentheses

3x-((4x+35))+41=0



We calculate terms in parentheses: -((4x+35)), so:

(4x+35)

We get rid of parentheses

4x+35

Back to the equation:

-(4x+35)



We get rid of parentheses

3x-4x-35+41=0

We add all the numbers together, and all the variables

-1x+6=0

We move all terms containing x to the left, all other terms to the right

-x=-6

x=-6/-1

x=+6

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