(3x+4)/4=(2x-8)/3

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Solution for (3x+4)/4=(2x-8)/3 equation: 



(3x+4)/4=(2x-8)/3

We move all terms to the left:

(3x+4)/4-((2x-8)/3)=0

We calculate fractions


3x/()+(-((2x-8)*4)/()=0



We calculate terms in parentheses: +(-((2x-8)*4)/(), so:

-((2x-8)*4)/(

We multiply all the terms by the denominator


-((2x-8)*4)



We calculate terms in parentheses: -((2x-8)*4), so:

(2x-8)*4

We multiply parentheses

8x-32

Back to the equation:

-(8x-32)



We get rid of parentheses

-8x+32

Back to the equation:

+(-8x+32)



We get rid of parentheses

3x/()-8x+32=0

We multiply all the terms by the denominator


3x-8x*()+32*()=0

We add all the numbers together, and all the variables

3x-8x*()=0

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