(3x+4)/4-(2x+3)/6=(x+1)/3

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Solution for (3x+4)/4-(2x+3)/6=(x+1)/3 equation: 


x in (-oo:+oo)

(3*x+4)/4-((2*x+3)/6) = (x+1)/3 // - (x+1)/3

(3*x+4)/4-((2*x+3)/6)-((x+1)/3) = 0

(3*x+4)/4+(-1*(2*x+3))/6+(-1*(x+1))/3 = 0

(3*6*(3*x+4))/(3*4*6)+(-1*3*4*(2*x+3))/(3*4*6)+(-1*4*6*(x+1))/(3*4*6) = 0

3*6*(3*x+4)-1*3*4*(2*x+3)-1*4*6*(x+1) = 0

30*x-24*x-24+36 = 0

6*x+12 = 0

(6*x+12)/(3*4*6) = 0

(6*x+12)/(3*4*6) = 0 // * 3*4*6

6*x+12 = 0

6*x+12 = 0 // - 12

6*x = -12 // : 6

x = -12/6

x = -2

x = -2

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