(3x+4)-2x=3(2x+4)-8

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Solution for (3x+4)-2x=3(2x+4)-8 equation: 



(3x+4)-2x=3(2x+4)-8

We move all terms to the left:

(3x+4)-2x-(3(2x+4)-8)=0

We add all the numbers together, and all the variables

-2x+(3x+4)-(3(2x+4)-8)=0

We get rid of parentheses

-2x+3x-(3(2x+4)-8)+4=0



We calculate terms in parentheses: -(3(2x+4)-8), so:

3(2x+4)-8

We multiply parentheses

6x+12-8

We add all the numbers together, and all the variables

6x+4

Back to the equation:

-(6x+4)



We add all the numbers together, and all the variables

x-(6x+4)+4=0

We get rid of parentheses

x-6x-4+4=0

We add all the numbers together, and all the variables

-5x=0

x=0/-5

x=0

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