(3x+4)-(2x2)=21

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Solution for (3x+4)-(2x2)=21 equation: 



(3x+4)-(2x^2)=21

We move all terms to the left:

(3x+4)-(2x^2)-(21)=0

determiningTheFunctionDomain
-2x^2+(3x+4)-21=0

We get rid of parentheses

-2x^2+3x+4-21=0

We add all the numbers together, and all the variables

-2x^2+3x-17=0

a = -2; b = 3; c = -17;
Δ = b2-4ac
Δ = 32-4·(-2)·(-17)
Δ = -127
Delta is less than zero, so there is no solution for the equation

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