(3x+4)+(6x-5)=62

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Solution for (3x+4)+(6x-5)=62 equation: 



(3x+4)+(6x-5)=62

We move all terms to the left:

(3x+4)+(6x-5)-(62)=0

We get rid of parentheses

3x+6x+4-5-62=0

We add all the numbers together, and all the variables

9x-63=0

We move all terms containing x to the left, all other terms to the right

9x=63

x=63/9

x=7

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