(3x+4)+(5y-1)=10-16i

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Solution for (3x+4)+(5y-1)=10-16i equation:


Simplifying
(3x + 4) + (5y + -1) = 10 + -16i

Reorder the terms:
(4 + 3x) + (5y + -1) = 10 + -16i

Remove parenthesis around (4 + 3x)
4 + 3x + (5y + -1) = 10 + -16i

Reorder the terms:
4 + 3x + (-1 + 5y) = 10 + -16i

Remove parenthesis around (-1 + 5y)
4 + 3x + -1 + 5y = 10 + -16i

Reorder the terms:
4 + -1 + 3x + 5y = 10 + -16i

Combine like terms: 4 + -1 = 3
3 + 3x + 5y = 10 + -16i

Solving
3 + 3x + 5y = 10 + -16i

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + 3x + -3 + 5y = 10 + -3 + -16i

Reorder the terms:
3 + -3 + 3x + 5y = 10 + -3 + -16i

Combine like terms: 3 + -3 = 0
0 + 3x + 5y = 10 + -3 + -16i
3x + 5y = 10 + -3 + -16i

Combine like terms: 10 + -3 = 7
3x + 5y = 7 + -16i

Add '-5y' to each side of the equation.
3x + 5y + -5y = 7 + -16i + -5y

Combine like terms: 5y + -5y = 0
3x + 0 = 7 + -16i + -5y
3x = 7 + -16i + -5y

Divide each side by '3'.
x = 2.333333333 + -5.333333333i + -1.666666667y

Simplifying
x = 2.333333333 + -5.333333333i + -1.666666667y

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