(3x+4)+(2x+1)=5(x-1)+8

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Solution for (3x+4)+(2x+1)=5(x-1)+8 equation:


Simplifying
(3x + 4) + (2x + 1) = 5(x + -1) + 8

Reorder the terms:
(4 + 3x) + (2x + 1) = 5(x + -1) + 8

Remove parenthesis around (4 + 3x)
4 + 3x + (2x + 1) = 5(x + -1) + 8

Reorder the terms:
4 + 3x + (1 + 2x) = 5(x + -1) + 8

Remove parenthesis around (1 + 2x)
4 + 3x + 1 + 2x = 5(x + -1) + 8

Reorder the terms:
4 + 1 + 3x + 2x = 5(x + -1) + 8

Combine like terms: 4 + 1 = 5
5 + 3x + 2x = 5(x + -1) + 8

Combine like terms: 3x + 2x = 5x
5 + 5x = 5(x + -1) + 8

Reorder the terms:
5 + 5x = 5(-1 + x) + 8
5 + 5x = (-1 * 5 + x * 5) + 8
5 + 5x = (-5 + 5x) + 8

Reorder the terms:
5 + 5x = -5 + 8 + 5x

Combine like terms: -5 + 8 = 3
5 + 5x = 3 + 5x

Add '-5x' to each side of the equation.
5 + 5x + -5x = 3 + 5x + -5x

Combine like terms: 5x + -5x = 0
5 + 0 = 3 + 5x + -5x
5 = 3 + 5x + -5x

Combine like terms: 5x + -5x = 0
5 = 3 + 0
5 = 3

Solving
5 = 3

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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