(3x+4)+(1x+1)=2(x+2)

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Solution for (3x+4)+(1x+1)=2(x+2) equation:


Simplifying
(3x + 4) + (1x + 1) = 2(x + 2)

Reorder the terms:
(4 + 3x) + (1x + 1) = 2(x + 2)

Remove parenthesis around (4 + 3x)
4 + 3x + (1x + 1) = 2(x + 2)

Reorder the terms:
4 + 3x + (1 + 1x) = 2(x + 2)

Remove parenthesis around (1 + 1x)
4 + 3x + 1 + 1x = 2(x + 2)

Reorder the terms:
4 + 1 + 3x + 1x = 2(x + 2)

Combine like terms: 4 + 1 = 5
5 + 3x + 1x = 2(x + 2)

Combine like terms: 3x + 1x = 4x
5 + 4x = 2(x + 2)

Reorder the terms:
5 + 4x = 2(2 + x)
5 + 4x = (2 * 2 + x * 2)
5 + 4x = (4 + 2x)

Solving
5 + 4x = 4 + 2x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-2x' to each side of the equation.
5 + 4x + -2x = 4 + 2x + -2x

Combine like terms: 4x + -2x = 2x
5 + 2x = 4 + 2x + -2x

Combine like terms: 2x + -2x = 0
5 + 2x = 4 + 0
5 + 2x = 4

Add '-5' to each side of the equation.
5 + -5 + 2x = 4 + -5

Combine like terms: 5 + -5 = 0
0 + 2x = 4 + -5
2x = 4 + -5

Combine like terms: 4 + -5 = -1
2x = -1

Divide each side by '2'.
x = -0.5

Simplifying
x = -0.5

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