(3x+4)(x+1)=0

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Solution for (3x+4)(x+1)=0 equation:


Simplifying
(3x + 4)(x + 1) = 0

Reorder the terms:
(4 + 3x)(x + 1) = 0

Reorder the terms:
(4 + 3x)(1 + x) = 0

Multiply (4 + 3x) * (1 + x)
(4(1 + x) + 3x * (1 + x)) = 0
((1 * 4 + x * 4) + 3x * (1 + x)) = 0
((4 + 4x) + 3x * (1 + x)) = 0
(4 + 4x + (1 * 3x + x * 3x)) = 0
(4 + 4x + (3x + 3x2)) = 0

Combine like terms: 4x + 3x = 7x
(4 + 7x + 3x2) = 0

Solving
4 + 7x + 3x2 = 0

Solving for variable 'x'.

Factor a trinomial.
(4 + 3x)(1 + x) = 0

Subproblem 1

Set the factor '(4 + 3x)' equal to zero and attempt to solve: Simplifying 4 + 3x = 0 Solving 4 + 3x = 0 Move all terms containing x to the left, all other terms to the right. Add '-4' to each side of the equation. 4 + -4 + 3x = 0 + -4 Combine like terms: 4 + -4 = 0 0 + 3x = 0 + -4 3x = 0 + -4 Combine like terms: 0 + -4 = -4 3x = -4 Divide each side by '3'. x = -1.333333333 Simplifying x = -1.333333333

Subproblem 2

Set the factor '(1 + x)' equal to zero and attempt to solve: Simplifying 1 + x = 0 Solving 1 + x = 0 Move all terms containing x to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + x = 0 + -1 Combine like terms: 1 + -1 = 0 0 + x = 0 + -1 x = 0 + -1 Combine like terms: 0 + -1 = -1 x = -1 Simplifying x = -1

Solution

x = {-1.333333333, -1}

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