(3x+4)(2x+11)=0

Solution for (3x+4)(2x+11)=0 equation:

(3x+4)(2x+11)=0

We multiply parentheses ..

(+6x^2+33x+8x+44)=0

We get rid of parentheses

6x^2+33x+8x+44=0

We add all the numbers together, and all the variables

6x^2+41x+44=0

a = 6; b = 41; c = +44;
Δ = b2-4ac
Δ = 412-4·6·44
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{625}=25$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(41)-25}{2*6}=\frac{-66}{12}
=-5+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(41)+25}{2*6}=\frac{-16}{12}
=-1+1/3
$