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(3x+36)(8x+6)=180
We move all terms to the left:
(3x+36)(8x+6)-(180)=0
We multiply parentheses ..
(+24x^2+18x+288x+216)-180=0
We get rid of parentheses
24x^2+18x+288x+216-180=0
We add all the numbers together, and all the variables
24x^2+306x+36=0
a = 24; b = 306; c = +36;
Δ = b2-4ac
Δ = 3062-4·24·36
Δ = 90180
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{90180}=\sqrt{36*2505}=\sqrt{36}*\sqrt{2505}=6\sqrt{2505}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(306)-6\sqrt{2505}}{2*24}=\frac{-306-6\sqrt{2505}}{48} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(306)+6\sqrt{2505}}{2*24}=\frac{-306+6\sqrt{2505}}{48} $
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