(3x+35)=(2x+46)

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Solution for (3x+35)=(2x+46) equation: 



(3x+35)=(2x+46)

We move all terms to the left:

(3x+35)-((2x+46))=0

We get rid of parentheses

3x-((2x+46))+35=0



We calculate terms in parentheses: -((2x+46)), so:

(2x+46)

We get rid of parentheses

2x+46

Back to the equation:

-(2x+46)



We get rid of parentheses

3x-2x-46+35=0

We add all the numbers together, and all the variables

x-11=0

We move all terms containing x to the left, all other terms to the right

x=11

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