(3x+33)=(2x+39)

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Solution for (3x+33)=(2x+39) equation: 



(3x+33)=(2x+39)

We move all terms to the left:

(3x+33)-((2x+39))=0

We get rid of parentheses

3x-((2x+39))+33=0



We calculate terms in parentheses: -((2x+39)), so:

(2x+39)

We get rid of parentheses

2x+39

Back to the equation:

-(2x+39)



We get rid of parentheses

3x-2x-39+33=0

We add all the numbers together, and all the variables

x-6=0

We move all terms containing x to the left, all other terms to the right

x=6

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