(3x+30)(x+70)(6x-30)(2x+50)=180

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Solution for (3x+30)(x+70)(6x-30)(2x+50)=180 equation: 



(3x+30)(x+70)(6x-30)(2x+50)=180

We move all terms to the left:

(3x+30)(x+70)(6x-30)(2x+50)-(180)=0

We multiply parentheses ..

(+3x^2+210x+30x+2100)(6x-30)(2x+50)-180=0

We multiply parentheses ..

(+3x^2+210x+30x+2100)(+12x^2+300x-60x-1500)-180=0

We move all terms containing x to the left, all other terms to the right

(+3x^2+210x+30x+2100)(+12x^2+300x-60x-1500)=180

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