(3x+3)/5=(4x+2)/2

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Solution for (3x+3)/5=(4x+2)/2 equation: 


x in (-oo:+oo)

(3*x+3)/5 = (4*x+2)/2 // - (4*x+2)/2

(3*x+3)/5-((4*x+2)/2) = 0

(3*x+3)/5+(-1*(4*x+2))/2 = 0

(2*(3*x+3))/(2*5)+(-1*5*(4*x+2))/(2*5) = 0

2*(3*x+3)-1*5*(4*x+2) = 0

-14*x-4 = 0

(-14*x-4)/(2*5) = 0

(-14*x-4)/(2*5) = 0 // * 2*5

-14*x-4 = 0

-14*x-4 = 0 // + 4

-14*x = 4 // : -14

x = 4/(-14)

x = -2/7

x = -2/7

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