(3x+3)+(x+3)=26

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Solution for (3x+3)+(x+3)=26 equation: 



(3x+3)+(x+3)=26

We move all terms to the left:

(3x+3)+(x+3)-(26)=0

We get rid of parentheses

3x+x+3+3-26=0

We add all the numbers together, and all the variables

4x-20=0

We move all terms containing x to the left, all other terms to the right

4x=20

x=20/4

x=5

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