(3x+3)(6x+5)=0

Solution for (3x+3)(6x+5)=0 equation:

(3x+3)(6x+5)=0

We multiply parentheses ..

(+18x^2+15x+18x+15)=0

We get rid of parentheses

18x^2+15x+18x+15=0

We add all the numbers together, and all the variables

18x^2+33x+15=0

a = 18; b = 33; c = +15;
Δ = b2-4ac
Δ = 332-4·18·15
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(33)-3}{2*18}=\frac{-36}{36}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(33)+3}{2*18}=\frac{-30}{36}
=-5/6
$