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(3x+3)(3x+15)=180
We move all terms to the left:
(3x+3)(3x+15)-(180)=0
We multiply parentheses ..
(+9x^2+45x+9x+45)-180=0
We get rid of parentheses
9x^2+45x+9x+45-180=0
We add all the numbers together, and all the variables
9x^2+54x-135=0
a = 9; b = 54; c = -135;
Δ = b2-4ac
Δ = 542-4·9·(-135)
Δ = 7776
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{7776}=\sqrt{1296*6}=\sqrt{1296}*\sqrt{6}=36\sqrt{6}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(54)-36\sqrt{6}}{2*9}=\frac{-54-36\sqrt{6}}{18} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(54)+36\sqrt{6}}{2*9}=\frac{-54+36\sqrt{6}}{18} $
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