(3x+28)+(5x+52)=(2x-10)

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Solution for (3x+28)+(5x+52)=(2x-10) equation: 



(3x+28)+(5x+52)=(2x-10)

We move all terms to the left:

(3x+28)+(5x+52)-((2x-10))=0

We get rid of parentheses

3x+5x-((2x-10))+28+52=0



We calculate terms in parentheses: -((2x-10)), so:

(2x-10)

We get rid of parentheses

2x-10

Back to the equation:

-(2x-10)



We add all the numbers together, and all the variables

8x-(2x-10)+80=0

We get rid of parentheses

8x-2x+10+80=0

We add all the numbers together, and all the variables

6x+90=0

We move all terms containing x to the left, all other terms to the right

6x=-90

x=-90/6

x=-15

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