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(3x+28)+(11x+12)=180
We move all terms to the left:
(3x+28)+(11x+12)-(180)=0
We get rid of parentheses
3x+11x+28+12-180=0
We add all the numbers together, and all the variables
14x-140=0
We move all terms containing x to the left, all other terms to the right
14x=140
x=140/14
x=10
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