(3x+25)+(2x+35)=160

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Solution for (3x+25)+(2x+35)=160 equation:



(3x+25)+(2x+35)=160
We move all terms to the left:
(3x+25)+(2x+35)-(160)=0
We get rid of parentheses
3x+2x+25+35-160=0
We add all the numbers together, and all the variables
5x-100=0
We move all terms containing x to the left, all other terms to the right
5x=100
x=100/5
x=20

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