(3x+25)(5x-35)=180

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Solution for (3x+25)(5x-35)=180 equation:



(3x+25)(5x-35)=180
We move all terms to the left:
(3x+25)(5x-35)-(180)=0
We multiply parentheses ..
(+15x^2-105x+125x-875)-180=0
We get rid of parentheses
15x^2-105x+125x-875-180=0
We add all the numbers together, and all the variables
15x^2+20x-1055=0
a = 15; b = 20; c = -1055;
Δ = b2-4ac
Δ = 202-4·15·(-1055)
Δ = 63700
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{63700}=\sqrt{4900*13}=\sqrt{4900}*\sqrt{13}=70\sqrt{13}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-70\sqrt{13}}{2*15}=\frac{-20-70\sqrt{13}}{30} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+70\sqrt{13}}{2*15}=\frac{-20+70\sqrt{13}}{30} $

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