(3x+21)(2x-8)=144

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Solution for (3x+21)(2x-8)=144 equation:



(3x+21)(2x-8)=144
We move all terms to the left:
(3x+21)(2x-8)-(144)=0
We multiply parentheses ..
(+6x^2-24x+42x-168)-144=0
We get rid of parentheses
6x^2-24x+42x-168-144=0
We add all the numbers together, and all the variables
6x^2+18x-312=0
a = 6; b = 18; c = -312;
Δ = b2-4ac
Δ = 182-4·6·(-312)
Δ = 7812
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{7812}=\sqrt{36*217}=\sqrt{36}*\sqrt{217}=6\sqrt{217}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-6\sqrt{217}}{2*6}=\frac{-18-6\sqrt{217}}{12} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+6\sqrt{217}}{2*6}=\frac{-18+6\sqrt{217}}{12} $

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