(3x+2)=(6x+118)

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Solution for (3x+2)=(6x+118) equation: 



(3x+2)=(6x+118)

We move all terms to the left:

(3x+2)-((6x+118))=0

We get rid of parentheses

3x-((6x+118))+2=0



We calculate terms in parentheses: -((6x+118)), so:

(6x+118)

We get rid of parentheses

6x+118

Back to the equation:

-(6x+118)



We get rid of parentheses

3x-6x-118+2=0

We add all the numbers together, and all the variables

-3x-116=0

We move all terms containing x to the left, all other terms to the right

-3x=116

x=116/-3

x=-38+2/3

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