(3x+2)=(5x+18)+(x+16)

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Solution for (3x+2)=(5x+18)+(x+16) equation: 



(3x+2)=(5x+18)+(x+16)

We move all terms to the left:

(3x+2)-((5x+18)+(x+16))=0

We get rid of parentheses

3x-((5x+18)+(x+16))+2=0



We calculate terms in parentheses: -((5x+18)+(x+16)), so:

(5x+18)+(x+16)

We get rid of parentheses

5x+x+18+16

We add all the numbers together, and all the variables

6x+34

Back to the equation:

-(6x+34)



We get rid of parentheses

3x-6x-34+2=0

We add all the numbers together, and all the variables

-3x-32=0

We move all terms containing x to the left, all other terms to the right

-3x=32

x=32/-3

x=-10+2/3

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